[" 9."1cc" of "N_(2)O" at "NTP" contains "],[" (a) "(1.8)/(224)times10^(22)" atoms "],[" (b) "(6.02)/(22400)times10^(23)" molecules "]

I cc N_(2)O at NTP contains

I cc N_(2)O at NTP contains

2.24 L of N_2 at N.T.P. contain same number of molecules as are present in

1 ml of hydrogen gas at NTP contains molecules equal to

N-="CC"H_(2)COOH

Three closed vessels A, B and C are at the same temperature T and contain gases. Vessel A contains only O_(2) , B contains only N_(2) and C contains a mixture of equal quantities of O_(2) and N_(2) . If the rms speed of O_(2) molecules in vessel A is v_(1) and that of N_(2) molecules in vessel B is v_(2) then the rms speed of O_(2) molecules in vessel C is

1 ml of H_(2)O_(2) solution given 10 ml of O_(2) at NTP. It is :

1 ml of H_(2)O_(2) solution given 10 ml of O_(2) at NTP. It is :