(y^(2)+7y+10)-:(y+5)

Factorise the expressions and divide them as directed. (y^2 + 7y + 10) div (y+5)

On dividing 5y^(3)- 2y^(2) - 7y + 1 by y, what will be the remainder ?

Factorise: 12(y^(2)+7y)^(2)-8(y^(2)+7y)(2y-1)-15(2y-1)^(2)

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Subtract: (-2y^(2)+(1)/(2)y-3) om 7y^(2)-2y+10

I. x^(2) - 5x - 14 = 0" "II. Y^(2) + 7y + 10 = 0