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int(-1)^1(x^3|x|+1)/(x^2+2|x|+1)dx=aln2+...

`int_(-1)^1(x^3|x|+1)/(x^2+2|x|+1)dx=aln2+bt h e n` `a=2; b=1` (b) `a=2; b=0` `a=2; b=-2` (d) `a=4; b=-1`

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