`f(x)={{:(2-x",","when",x lt2 ),( 2+x",", "when",xge2):}` is discontinuous at x =2

f(x)={{:(3-x",","when",x le0, ),( x^(2)",", "when",xgt0):} is discontinuous at x=0

f(x)={{:(cosx",","when",x ge0, ),(-cosx",", "when", x lt0):} is discontinuous at x =0

Show that the funcation f(x)={{:(3x-2",", " when ", x le0),(x+1",", " when ", x gt 0):} is discontinuous at x =0

f(x)={{:(2x",","when",x lt0, ),(2",", "when", x =2),(x^(2)",","when",xgt2):} is discontinuous at x=0

f(x)={{:(-x",","when",x lt0, ),(1",", "when", x =0),(x",","when",xgt0):} is discontinuous at x = 0

A function f (x) is defined as follows: f(x)={{:(x+2,"when "xlt2),(x^(2)-1,"when "xge2):} Show that f (x) is discontinuous at x = 2 and the jump of the function at this point is -1 .

Show that the function f(x)={{:(x+(x+2)/(|x+2|),"when " xne-2),(" "-1,"when " x=-2):} is dicontinuous at x=-2 Also find the jump of f (x) at this point of discontinuity.

f(x)={{:(3k-2x", when "xlt1),(2k+1", when "xge1):} at x = 1

If f(x) = {(kx-1, "when" x lt 2),(x+1,"when" x gt 2),(3, "when: x = 2):} is continuous at x = 2 , then k =

If f(x) = {(kx-1, "when" x lt 2),(x+1,"when" x gt 2),(3, "when: x = 2):} is continuous at x = 2 , then k =