Tro . Ques- of stone of mass m' etied to the end of a string, seis cuheiled around the horirental surface. The Length of the string reduced gradually keeping angular momentum aboi of the stone about the centre ar circle constant. Then the tension in the string Ogiven by T = "Dah cubere A cis constant, s' is the instantaneous radius of the circle. find me

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T = Ar^2 where A is a constant, r is the instantaneous radius fo the circle and n=....

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T = Ar^n where A is a constant, r is the instantaneous radius of the circle and n=....

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T = Ar^n where A is a constant, r is the instantaneous radius of the circle and n=....

A stone of mass m tied to the end of a string is whirled around in a horizontal circle (neglect force du eto grvaity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then the tension in the given by T = A r^(n) , where A is a constant and r is instantaneous radius of the circle. Show that n = - 3 .

A stone of mass m, tied to the end of a string, is. whirled around in a horizontal circle (neglect gravity). The length of the string is reduced gradually such that mvr = constant. Then, the tension in the string is given · by T = Ar '', where A is a constant and r is the instantaneous radius of the circle. Then, n is equal to:

A stone of mass 2.0 kg is tied to the end of a string of 2m length. It is whirled in a horizontal circle. If the breaking tension of the string is 400 N, calculate the maximum velocity of the stone.

A stone of mass 2.0 kg is tied to the end of a string of 2m length. It is whirled in a horizontal circle. If the breaking tension of the string is 400 N, calculate the maximum velocity of the stone.