If the term`sqrt(1+1/2^2+1/3^2)+....+=n-1/n`

Find the sum of n terms \ of the series: 1/(1. 2)+1/(2. 3)+1/(3. 4)+...............+1/(n.(n+1))

Find the sum of n terms \ of the series: 1/(1. 2)+1/(2. 3)+1/(3. 4)+...............+1/(n.(n+1))

The sum to n terms of the series 1+2(1+1/n)+3(1+1/n)^2+....... is given by

Find the sum of the GP : (i) sqrt(7)+sqrt(21)+3sqrt(7)+... to n terms (ii) 1-1/3+1/3^(2)-1/3^(3)+... to n terms (iii) 1-a+a^(2)-a^(3)+... to n terms (a ne 1) (iv) x^(3)+x^(5)+x^(7)+... to terms (v) x(x+y)+x^(2)(x^(2)+y^(2))+x^(3) (x^(3)+y^(3))+... to n terms

lim_(n->oo)[1/sqrt(2n-1^2) +1/sqrt(4n-2^2)+1/sqrt(6n-3^2)+...+1/n]

Find n^(th) term of the series 1+(1+2)+(1+2+3)+.... Find the sum to n terms of the series

Find the sum of n terms \ of the series: 1/(1. 2)+1/(2. 3)+1/(3. 4)+dot+ 1/n dot((n+1))

The sum to n terms of the series 1+2 (1+(1)/(n))+3 (1+(1)/(n))^(2)+ cdots is given by

The sum of n terms of the series 1+2 (1 + (1)/(n)) +3 (1+ (1)/(n))^(2) + ….is

Evaluate: underset(nrarralpha)Lt[1/(sqrt(2n-1^2)) +1/(sqrt(4n-2^2))+1/sqrt(6n-3^2)+...+1/n]