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Find the equation of tangent to the coni...

Find the equation of tangent to the conic `x^2-y^2-8x+2y+11=0` at `(2,1)`

Text Solution

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Equation of the conic is ,
`x^2-y^2-8x+2y+11=0`
Differentiating it with respect to `x`,
`2x-2ydy/dx-8+2dy/dx = 0`
`=>dy/dx(2-2y) = 8-2x`
`=>dy/dx = (4-x)/(1-y)`
At point `(2,1)`,
`dy/dx = oo`
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