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[" 20.The amount of energy released in t...

[" 20.The amount of energy released in the fusion "],[" of two "H^(2)" to form a "2^(" He ")" nucleus will be "],[" [Binding energy per nucleon of "H^(2)=1.1Mev],[" Binding energy per nucleon of "Ae^(4)=7Mev]],[" 1) "8.1MeV2" ) "5.9MeV3)23.6MeV4" ) "2MeV]

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The amount of energy released in the fusion of two ._(1)H^(2) to form a ._(2)He^(4) nucleus will be {Binding energy per nucleon of ._(1)He^(2)=1.1 MeV Binding energy per nucleon of ._(2)He^(4)=7 MeV ]

The binding energy per nucleon of _2He^4 is 7.075 MeV. What is its total binding energy?

The mass defect of ""_(2)^(4)He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

The binding energy of ._(2)^(4)He is 28.57 MeV. What shall be the binding energy per nucleon of this element?

The mass defect of He_(2)^(4) He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

Assertion : Binding energy per nucleon is of the order of MeV. Reason: 1 MeV=1.6xx10^-13J .

Assertion : Binding energy per nucleon is of the order of MeV. Reason: 1 MeV=1.6xx10^-13J .

Two deuterons udnergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)

Two deuterons udnergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)