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(a+2x^(3))^(16)" apt "14" at "4a" sild a...

(a+2x^(3))^(16)" apt "14" at "4a" sild anflorel "

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4 (2x-3) ^ (2) - (2x-3) -14 = 0

Solve : (7x +3)/(4) + (9x -5)/(8) = (16x-3)/(16) The following steps are involved in solving the above problem. Arrange them in sequential order (A) x = (-5)/(30) = (-1)/(6) (B) (7x + 3)/(4) + (9x -5)/(8) = (16x-3)/(16) rArr (14x + 6 + 9x -5)/(8) = (16x -3)/(16) (C) (23x + 1)/(8) = (16x -3)/(16) rArr 23x + 1 = (16x -3)/(2) (D) 46x + 2 = 16x - 3 rArr 30 x = -5

If the coefficients of x^3 and x^4 in the expansion of (1""+a x+b x^2)""(1-2x)^(18) in powers of x are both zero, then (a, b) is equal to (1) (16 ,(251)/3) (3) (14 ,(251)/3) (2) (14 ,(272)/3) (4) (16 ,(272)/3)

If the coefficients of x^3 and x^4 in the expansion of (1""+a x+b x^2)""(1-2x)^(18) in powers of x are both zero, then (a, b) is equal to (1) (16 ,(251)/3) (3) (14 ,(251)/3) (2) (14 ,(272)/3) (4) (16 ,(272)/3)

If the coefficients of x^3 and x^4 in the expansion of (1""+a x+b x^2)""(1-2x)^(18) in powers of x are both zero, then (a, b) is equal to (1) (16 ,(251)/3) (3) (14 ,(251)/3) (2) (14 ,(272)/3) (4) (16 ,(272)/3)

If the coefficients of x^3 and x^4 in the expansion of (1""+a x+b x^2)""(1-2x)^(18) in powers of x are both zero, then (a, b) is equal to (1) (16 ,(251)/3) (3) (14 ,(251)/3) (2) (14 ,(272)/3) (4) (16 ,(272)/3)

If (x-k) is the HCF of 3x^(2)+14x+16 and (6x^(3)+11x^(2)-4x-4) ,then the value of k