Let `a,b,c` be coordinates of vectices `A,B,C` of `DeltaABC,[a,b,c` are complex numbers]. If each of `a,b,c` are unit modulus and exists `alpha` such that `(a sec alpha)+b+(c tan alpha)=0,[alpha in(0,pi/2)].` then area of `DeltaABC` can be

Let a,b,c be coordinates of vertices A,B,C of Delta ABC.[a,b,c are complec numbers].If each of a,b,c are of unit modulus and there exists alpha such that (a sec alpha)+b+(c tan alpha)=0[alpha in(o,(pi)/(2))], Then area of the triangle Delta ABC can be

If a alpha b and b alpha c , show that a^3+b^3+c^3 alpha 5 abc .

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha - d tan alpha=c , then eliminate alpha from above equations.

If det[[a,b,a alpha+bb,c,b alpha+ca alpha+b,b alpha+c,0]]=0 then

If a sec alpha +btan alpha=d and bsec alpha +a tan alpha=c prove that a^2+c^2=b^2+d^2

If |(a,b,a alpha+b),(b,c, b alpha+c),(a alpha+b, b alpha+c,0)|=0 then

If : a * sec alpha+b * tan alpha=m and : atan alpha+b * sec alpha=n, then : a^(2)-b^(2) =