" If "z+sqrt(2)|z+1|+i=0" and "z=x+iy," then "

If z+sqrt(2)|z+1|+i=0, then z equals

The number of solutions of sqrt(2)|z-1|=z-i, where z=x+iy is (A) 0 (B) 1 (C) 2 (D) 3

The number of solutions of sqrt(2)|z-1|=z-i, where z=x+iy is (A) 0 (B) 1 (C) 2 (D) 3

If z = x + iy such that cos z = 2, then z =

If Re((z-1)/(2z+i))=1, where z=x+iy ,then the point (x,y) lies on a

Let z = x + iy be a non - zero complex number such that z^(2) = I |z|^(2) , where I = sqrt(-1) then z lies on the :

If (z - i)/(z +1) is purely imaginary then the locus of z = x +iy is

If z=x+iy , show that sqrt(2)|z| ge |x|+ |y| .