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[" 2.In "Delta ABC" ,then Prove that; "],[(b-c)/(a)=(tan(B)/(2)-tan(C)/(2))/(tan(B)/(2)+tan(C)/(2))]

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In any Delta ABC, prove that : ((a-b)/(c))=(tan((A)/(2))-tan((B)/(2)))/(tan((A)/(2))+tan((B)/(2)))

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In Delta ABC , if x=tan((B-C)/(2))tan.(A)/(2),y=tan((C-A)/(2))tan.(B)/(2) and z=tan((A-B)/(2))tan.(C)/(2) then (x+y+z)= .

In Delta ABC, tan ""A/2 * tan ""(B)/(2) + tan""(B)/(2) * tan""(C)/(2) + tan ""(C)/(2)* tan""A/2=