[" QR "=(QT)/(PR)" and "L1=L2." Show "],...

[" QR "=(QT)/(PR)" and "L1=L2." Show "],[" Infig."6.36,(QT)/(PR)" and "L1=L2." Show "],[" Infig."[" that "Delta PQS-Delta TQR," PR and "QR" of "D],[" that "/_PQS-A," sides "RTS" .Show that "]]

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In Fig . (QR)/(QS) = (QT)/(PR)and |__ul(1)=|__ul(2) . Show that Delta PQS ~ Delta TQR

In the given figure (QR)/(QS)=(QT)/(PR)" and "/_1= /_2 . Show that DeltaPQS ~ DeltaTQR .

In Fig (QR)/(QS)=(QT)/(PR)= and angle1 = angle2. show that DeltaPQS ~DeltaTQR .

In the figure beside , (QR)/(QS)=(QT)/(PR) and /_1=/_2 . Prove that DeltaPQS~DeltaTQR .

In the given figure, (QT)/(PR) = (QR)/(QS) and angle 1 = angle 2 Prove that Delta PQS ~ Delta TQR .

In Fig. 6.36, (QR)/(QS)=(QT)/(PR) and angle 1=angle 2 .Show that trianglePQS~triangle TQR

In fig., (QR)/(QS)=(QT)/(PR) and angle1=angle2 . Show that trianglePQS~triangleTQR . .

In Delta DEF and Delta PQR , if PQ =DE, EF=PR and FD =QR, then