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(19)/(43)+(1)/(2+(1)/(3+))...

(19)/(43)+(1)/(2+(1)/(3+))

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Find (1)/(3)+(1)/(2.3^(2))+(1)/(3.3^(3))+(1)/(4.3^(4))+….oo=?

(1)/(3)+(1)/(2.3^(2))+(1)/(3.3^(3))+(1)/(4.3^(4))+….oo=

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (19)/(64) (b) (64)/(19) (27)/(16) (d) (-19)/(64)

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (a) (19)/(64) (b) (64)/(19) (c) (27)/(16) (d) (-19)/(64)

Evaluate: ((0. 43) ^(3) + (1. 47) ^(3) + (1.1) ^(3) - 3 xx 0. 43 xx 1 . 47 xx 1.1)/(( ( 0. 43) ^(2) + (1. 47) ^(2) + (1.1) ^(2) -0. 43 xx 1. 43)- 0. 43 xx 1.1 - 1.47 xx 1.1)

(1)/(log_(2)x)+(1)/(log_(3)x)+......(1)/(log_(43)x)=(1)/(log_(43)!x)

If 1, (1)/(2) log_(3) (3^(1-x) + 2), log_(3) (4.3^(x)-1) are in A.P. then x equals