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" Ase anfrom far "int(0)^( pi/2)log cos ...

" Ase anfrom far "int_(0)^( pi/2)log cos xdx=-(pi)/(2)log2

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int_(0)^(pi//2)log(cosx)dx=

int_(0)^( pi)log xdx

int_(0)^(pi//2)x cot x dx=(pi)/(2)(log2)

int_(0)^((pi)/(2))log(cos x)dx=

int_(0)^(pi//2)log(sinx)dx=

int_(0)^(pi//2)(2logcosx-logsin2x)\ dx=-(pi)/(2)log2

int_(0)^(pi//2)log(tanx)dx=

int_(0)^(pi)log(1+cosx)dx=-pi(log2)

int_(0)^(pi//2) log (cotx ) dx=

int_(0)^(pi//2) log (cotx ) dx=