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" 19."(dy)/(dx)=y tan2x," if "x=0,y=2...

" 19."(dy)/(dx)=y tan2x," if "x=0,y=2

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(dy)/(dx)=y tan x , y=1 when x=0

(dy)/(dx) = y tan x - 2 sinx

(dy)/(dx)=tan^(2)(x+y)

Solve the following initial value problem: (dy)/(dx)=y \ tan2x ,\ y(0)=2

Solve the following initial value problem: (dy)/(dx)=tan2x,y(0)=2

(dy) / (dx) = tan ^ (2) (x + y)

Solve (dy)/(dx) =y^(2)tan 2x, " given that " y =2 " when " x =0 .

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0

(dy)/(dx) = y tan x, y = 1 when x = 0