Home
Class 12
MATHS
Let the line y=mx and the ellipse 2x^(2)...

Let the line `y=mx` and the ellipse `2x^(2)+y^(2)=1` intersect at a point P in the first quadrant. If the normal to this ellipse at P meets the co - ordinate axes at `(-(1)/(3sqrt2),0) and (0, beta)`, then `beta` is equal to

A

`2/sqrt3`

B

`(2sqrt2/3)`

C

`(sqrt2)/3`

D

`2/3`

Text Solution

Verified by Experts

The correct Answer is:
C

NA
Promotional Banner

Similar Questions

Explore conceptually related problems

The line y=2t^2 meets the ellipse (x^2)/(9)+(y^2)/(4)=1 in real points if

The line 2x+y=3 intersects the ellipse 4x^(2)+y^(2)=5 at two points. The point of intersection of the tangents to the ellipse at these point is

Consider any P on the ellipse x^(2)/25+y^(2)/9=1 in the firsty quadrant. Let r and then (r + s) is equal to

The line x=2y intersects the ellipse (x^(2))/4+y^(2)=1 at the points P and Q . The equation of the circle with PQ as diameter is

The line 2x+y=3 cuts the ellipse 4x^(2)+y^(2)=5 at points P and Q. If theta is the acute angle between the normals at P and Q, then theta is equal to

P is the extremity of the latuscrectum of ellipse 3x^(2)+4y^(2)=48 in the first quadrant. The eccentric angle of P is

If the line y=x+sqrt(3) touches the ellipse (x^(2))/(4)+(y^(2))/(1)=1 then the point of contact is

If the line y=mx meets the lines x+2y-1=0 and 2x-y+3=0 at the same point, then m is equal to

If the normal to the ellipse 3x^(2)+4y^(2)=12 at a point P on it is parallel to the line , 2x+y=4 and the tangent to the ellipse at P passes through Q (4,4) then Pq is equal to