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Two photons of energy 4eV and 4.5 eV inc...

Two photons of energy 4eV and 4.5 eV incident on two metals A and B respectively. Maximum kinetic energy for ejected electron is `T_A` for A and `T_B = T_A – 1.5 eV` for metal B. Relation between de-Broglie wavelength of ejected electron of A and B are `lambda_B = 2lambda_A` . The work function of metal B is–

A

3 eV

B

1.5 eV

C

4.5 eV

D

4 eV

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