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If tn=1/(4(n+2)(n+3)) for n=1,2,3, , ...

If `t_n=1/(4(n+2)(n+3)) `for` n=1,2,3, ,` then `1/(t_1)+1/(t_2)+1/(t_3)++1/(t_(2003))=` `(4006)/(3006)` b. `(3006)/(3007)` c. `(4006)/(3008)` d. `(4006)/(3009)`

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