Find the point on the ellipse `16 x^2+11 y^2=256` where the common tangent to it and the circle `x^2+y^2-2x=15` touch.

Find the point on the ellipse 16x^(2)+11y^(2)=256 where the common tangent to it and the circle x^(2)+y^(2)-2x=15 touch.

If the tangent at the point P(theta) to the ellipse 16 x^2+11 y^2=256 is also a tangent to the circle x^2+y^2-2x=15 , then theta= (a) (2pi)/3 (b) (4pi)/3 (c) (5pi)/3 (d) pi/3

If the tangent at the point P(theta) to the ellipse 16 x^2+11 y^2=256 is also a tangent to the circle x^2+y^2-2x=15 , then theta= (a) (2pi)/3 (b) (4pi)/3 (c) (5pi)/3 (d) pi/3

If the tangent at the point P(theta) to the ellipse 16x^(2)+11y^(2)=256 is also a tangent to the circle x^(2)+y^(2)-2x=15, then theta=(2 pi)/(3)( b )(4 pi)/(3) (c) (5 pi)/(3) (d) (pi)/(3)

If the tangent at the point (4 cos theta, (16)/(sqrt(11)) sin theta) to the ellipse 16x^(2) + 11y^(2) = 256 is also a tangent to the circle x^(2) + y^(2) - 2x - 15 = 0 , then the value of theta , is

If the tangent at the point (4 cos theta, (16)/(sqrt(11)) sin theta) to the ellipse 16x^(2) + 11y^(2) = 256 is also a tangent to the circle x^(2) + y^(2) - 2x - 15 = 0 , then the value of theta , is

if the tangent at the point (4 cos phi , (16)/(sqrt(11) )sin phi ) to the ellipse 16x^(2)+11y^(2) =256 Is also a tangent to the circle x^(2) +y^(2)-2x=15, then the value of phi is

if the tangent at the point (4 cos phi , (16)/(sqrt(11) )sin phi ) to the ellipse 16x^(2)+11y^(2) =256 Is also a tangent to the circle x^(2) +y^(2)-2x=15, then the value of phi is