Compound (A) on oxidation withg `OsO_(4)//NaIO_(4)` gives hexanedial.Structure of compound (A) will be:

Compound A on oxidation with OsO_4 // NaIO_4 gives cyclo hexanedial. Structure of compound A will be :

Compound A on oxidation with OsO_4//NaHSO_3 following by reaction with HIO_4 gives hexane 1,6 - di al .The structure of compound A can be given as

Compound A on oxidation with OsO_4//NaHSO_3 following by reaction with HIO_4 gives hexane 1,6 - di al .The structure of compound A can be given as

An aromatic compound (A), C_(8)H_(10) , on oxidation with acidic KMnO_(4) gives dibasic acid. The compound (A) on nitration gives three isomeric nitro derivatives. The compound (A) is:

An aromatic compound (A), C_(8)H_(10) , on oxidation with acidic KMnO_(4) gives dibasic acid. The compound (A) on nitration gives three isomeric nitro derivatives. The compound (A) is:

Unknown compound (A) on oxidation with hot basic KMnO_(4) gives only one compound whose structure is given below, Compound (A) will be:

Unknown compound A on oxidation with hot basic KMnO, gives only one compound structure of which is given below. HOOC - (CH_2)_4 - COOH . Compound A will be

Compound (A)(C_(12)H_(16)) on oxidation with acidic KMnO_(4) solution gives acetone and . Identify compound (A) .