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Given four lines whose equations are x +...

Given four lines whose equations are `x +2y -3=0, 2x+3y-4=0, 3x + 4y -7 = 0 and 4x + 5y-6=0`, then the lines are

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Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then:

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

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A triangle is formed by the lines whose equations are 3x+4y-6=0,12x-5y-3 = 0 and 4x-3y + 12 = 0 . Find the internal bisector of the angle opposite to the side 3x + 4y -6=0.

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The lines x+2y-5=0, 2x-3y+4=0,6x+4y-13=0

Determine whether or not the four straight lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0,4x+5y-6=0 are concurrent.