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Normal at (2, 2) to curve x^2 + 2xy - 3...

Normal at `(2, 2)` to curve `x^2 + 2xy - 3y^2 = 0` is L. Then perpendicular distance from origin to line L is

A

`4sqrt(2)`

B

`2`

C

`2sqrt(2)`

D

4

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The correct Answer is:
C
NA
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