The number of harmonic components in the oscillations are represented by, `y=4cos^(2)(2 tsin4t)`. What are their corresponding angular frequencies?

A wave is represented by y=0.4cos(8t-(x)/(2)) where x and y are in metres and t in seconds. The frequency of the wave is

Two simple harmonic motions are represented by y_(1)=4sin(4pit+pi//2) and y_(2)=3cos(4pit) . The resultant amplitude is

A harmonic oscillation is represented by y = 0.34 cos(3000 t + 0.74) where y and t are in mm and second respectively. Deduce amplitude, frequency and angular frequency, time period and intianl phase.

The displacement of a simple harmonic oscillator is given by y= 0.40 sin (440t +0.61) . For this, what are the value of angular frequency.

The superposition of two harmonic oscillations of the same direction results in the oscillation of a point according to the law x=a cos 2.1 t cos 50.0 t , where t is expressed in seconds. Find the angular frequencies of the constituent oscillations and the period with which they beat.

Displacement of a particle, in periodic motion, is represented by y = 4 cos^(2) ((t)/(2)) sin (1000t). If the equation is the superposition of n number of simple harmonic motion then n becomes

A simple harmonic motion is represented by x(t) = sin^(2)omega t - 2 cos^(2) omega t . The angular frequency of oscillation is given by