" (5) "int[log(log x)+1/(log)^(2)]dx

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int[log(log x)+(1)/((log x)^(2))]dx

"F i n d"int[log(logx)+1/((logx)^2)]dx Find log (log x)+ |dx 2 (log x)

int(log(log x)+(log x)^(-1))dx=

Evaluate: int(log(log x)+(1)/((log x)^(2)))dx

Evaluate : int [ log (log x) +(1)/((log x)^(2)) ] dx

int (log x-1)/((log x)^(2))dx=

int((log x)/((1+log x)^(2)))dx

int(log x-1)/((log x)^(2))dx

int [ log (log x) + (log x)^(-2)] dx is :