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" (iii) "cos6 theta=32cos^(6)theta-48cos...

" (iii) "cos6 theta=32cos^(6)theta-48cos^(4)theta+18cos^(2)theta-1

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Prove that cos6 theta=32cos^(6)theta-48cos^(4)theta+18cos^(4)theta-1

sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1

If sin theta+sin ^(2) theta+sin ^(3) theta=1 then cos ^(6) theta-4 cos ^(4) theta+8 cos ^(2) theta=

cos6x=32cos^(6)x-48cos^(4)x+18cos^(2)x-1

cos6x=32cos^(6)x-48cos^(4)x-18cos^(2)x-1

cos^(3)2 theta+3cos2 theta=4(cos^(6)theta-sin^(6)theta)

4cos6 theta cos4 theta cos2 theta=

2(sin^(6) theta + cos^(6)theta) - 3(sin^(4)theta + cos^(4)theta)+ 1 = 0