[" 19.Four some half cell reaction "11" .Amman "],[" below.On the basis of these mark "],[" answer."],[[" (i) "H_((aq))^(+)+e^(-)longrightarrow(1)/(2)H_(2(g))," if enter "],[" (ii) "2H_(2)O_((1))longrightarrow,O_(2(9))+4H_((aq))^(+)+4e_(i)]]

Potential for some half cell reactions are given below. On the basis of these mark the correct answer. (i) H^(+)(aq) + e^(-) rightarrow (1/2)H^(2)(g) E_(cell)^(@) = 0.00V (ii) 2H_(2)O(l) rightarrow O_(2)(g) + 4H^(+)(aq) + 4e^(-) , E_(cell) = 1.96V (iii) 2SO_(4)^(2-)(aq) rightarrow S_(2)O_(8)^(2-)(aq) + 2e^(-), E_(cell)^(@) = 1.96V

Potential for some half cell reactions are given below. On the basis of these mark the correct answer. (i) H^(+)(aq) + e^(-) rightarrow (1/2)H^(2)(g) E_(cell)^(@) = 0.00V (ii) 2H_(2)O(l) rightarrow O_(2)(g) + 4H^(+)(aq) + 4e^(-) , E_(cell) = 1.23V (iii) 2SO_(4)^(2-)(aq) rightarrow S_(2)O_(8)^(2-)(aq) + 2e^(-), E_(cell)^(@) = 1.96V

The reaction, 2H_(2)O_((l)) to 4H_((aq))^(+)+O_(2(g))+4e^(-) is

(iii) H_(2)SO_(4(aq)) + NaOH_((aq)) to Na_(2)SO_(4(aq)) + H_(2)O_((I))