[" 2."4lg289=17((x)/(5))," " "x=?],[[" (a) "10," (b) "5],[" (c) "20," (d) "(2)/(5)]]

If 289=17^(x/5) , then x = ?

If 289=17^(1/5x), then x=? a. 2/5 b. 8 c. 16 d. 32

5x^(2)-(17)/(2)x+(3)/(2)=0

(17(2-x)-5(x+12))/(1-7x)=8

If (4x + 5) : (3x + 11) = 13:17 , then (5x + 4) : (4x -1) =?

If (4x + 5) : (3x + 11) = 13:17, then (5x + 4): (4x -1) = ?

A root of the equation 17x^2 + 17x tan [2 tan^-1(1/5) - pi/4] - 10 = 0 is (i) 10/17 (ii) -1 (iii) -7/17 (iv) 1

Solve for x and y : 4x = 17 - (x - y)/(8) 2y + x = 2 + (5y + 2)/(3)

4x+3 ge 2x+ 17, 3x-5 lt -2