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In Fig. 10.64, BC is a tangent to the ci...

In Fig. 10.64, BC is a tangent to the circle with centre O.OE bisects AP. Prove that `Delta ABC ~ Delta AEO`

Text Solution

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`/_AEO and /_PEO`
OE=OE(same)
CP=EA(given)
OA=OD(radius)
`/_AEo cong /_PEO`
`/_AEO=/_PEO=90^0`
`/_AEO and /_ABC`
`/_A=/_A`(common)
...
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