" Exapplyne Sfixpress tan' "((cos x)/(1-sin x))*(pi)/(2)

Express 'tan ^(^^)(-1)((cos x)/(1-sin x)),-pi/2

Solve : tan^(-1)((cos x)/(1+sin x)) , -(pi)/(2) lt x lt (pi)/(2)

solve: tan^(-1) ((cos x)/(1-sin x)) = ((pi)/(4)+(x)/(2)) , (-3 pi)/(2)ltxlt(pi)/(2)

Prove that tan^(-1)((cos x)/(1+sin x))=(pi)/(4)-(x)/(2),|x in(-(pi)/(2),(pi)/(2))

If x in R and n in I then the determinant sin(n pi),sin x-cos x,log tan xcos x-sin x cos{(2n+1)(pi)/(2)},log cot xlog cot x,log tan x,tan(n pi)]|=

prove the following (cos2x)/(1+sin2x) = tan(pi/4-x)

The expression (tan(x-pi/2)cos((3pi)/2+x)-sin^3((7pi)/2-x))/(cos(x-pi/2)tan((3pi)/2+x) is equal to

If 0

simplify : tan^(-1) ""((a cos x- b sin x )/(b cos x + a sin x ) ) (- pi )/(2) lt x lt pi/2 , a/b tan x gt -1

Differentiate, tan^(-1) ((a cos x- b sin x)/(b cos x + a sin x)), (-pi)/(2) lt x lt (pi)/(2) and (a)/(b) tan x gt -1