Find the equation of the hyperbola with foci `(0,+-3)`and vertices `(0,+-(sqrt(11))/2)`

Explanation

To find the equation of the hyperbola with given foci and vertices, we can follow these steps:

### Step 1: Identify the structure of the hyperbola
Since the foci are located at (0, ±3) and the vertices at (0, ±√11/2), we can conclude that the hyperbola opens vertically. The standard form of the equation for a vertical hyperbola is:

\[ \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \]
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