STATEMENT-1 : Equivalent volume of `H_(2)` is 11.2 L at 1 atm and 273 K.
STATEMENT-2 : `1//2`mole `H_(2)` has produced when 1 mole of `H^(+)` (aq) accepted 1 mole of `e^(-)`.

This question has Statement I and Statement II. Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement - I : Equivalent volume of H_2 is 11.2 Lat1 atm and 273 K. Statement - II: 1/2 mole H_2 has produced when 1 mole of H^+ (aq) accepted 1 mole of e^-

STATEMENT -1 : 18 ml of H_(2)O and 18 ml of CO_(2) at 277 K have same no. of moles. and STATEMENT -2 : Density of H_(2)O is more than CO_(2) .

STATEMENT -1 : 18 ml of H_(2)O and 18 ml of CO_(2) at 277 K have same no. of moles. and STATEMENT -2 : Density of H_(2)O is more than CO_(2) .

Volume of 0.5 mole of a gas at 1 atm. Pressure and 273 K is

Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is

1 mole of [OH^(-)] is present in how many moles of H_(2)O ?

1 mole H_2O represents

The integral enthalpy of solution in kJ of one mole of H_(2)SO_(4) dissolved in n mole of water is given by : DeltaH_(s)=(75.6xxn)/(n+1.8) Calculate DeltaH for the following processes : (a) 1 mole of H_(2)SO_(4) dissolved in 2 mole of H_(2)O . (b) 1 mole of H_(2)SO_(4) dissolved in 7 mole of H_(2)O . (c ) 1 mole of H_(2)SO_(4) dissolved in 5 mole of H_(2)O . (d) solution (a) dissolved in 5 mole of H_(2)O . (e) 1 mole of H_(2)SO_(4) dissolved in excess of H_(2)O .

When 1 mole of PbS reacts completely with H_(2)O_(2)