" 6."quad " afg "a=cos theta+i sin theta" at "(1+a)/(1-a)

If a=cos theta+i sin theta then (1+a)/(1-a)=

If a = cos theta + i sin theta , then (1 + a)/(1 -a)

1 + cos theta + i sin theta | =?

(1)/(cos theta-i sin theta)

Solve (1)/(cos theta-i sin theta)

The argument of 1-cos theta-i sin theta is

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)

Prove each of the following identities : (i) (1+ cos theta + sin theta)/(1+ cos theta - sin theta) =(1+ sin theta)/(cos theta) (ii) (sin theta + 1- cos theta)/(cos theta - 1 + sin theta) = (1+ sin theta)/(cos theta)

(1+ sin theta - cos theta )/( 1+ sin theta + cos theta ) + (1+ sin theta + cos theta )/( 1+ sin theta - cos theta ) =