(x^(2)+y^(2))^(2)=xy[CBSE2009]

If x=2+3i and y=2-3i then find the values of : (x^(2)+xy+y^(2))/(x^(2)-xy+y^(2))

x-x^(2)y+xy^(2)-y

The factor of (x^(2010)+y^(2010))^(2010!)-(x^(2009!))^(2010^(2))-(y^(2009!))^(2010^(2)) is: a.x^(2009)b.y^(2009)c.(xy)^(2009!)d.(xy)^(2010)

Simplify: 2x^(2)+3xy -3y^(2)+x^(2)-xy+y^(2)

Find the continued product of x+y,x-y,x^(2)+xy+y^(2),x^(2)-xy+y^(2)

Add : 4x^(2)y, - 3xy^(2), -5xy^(2), 5x^(2)y

The solution of the differential equation y(xy+2x^(2)y^(2))dx+x(xy-x^(2)y^(2))dy=0, is given by