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[" In "x^(2)+5x+6," we find "ab=f" proto...

[" In "x^(2)+5x+6," we find "ab=f" protonsethe following expressions "14.2],[" The factors then will "b" part "8a+16" (ii) "p^(2)-10p+25" .(iii) "25m+9],[" ty "a=6,b=1." For thes "([1+b^(2)-88bc+36z^(2)," (ii) "p^(2)-10p+25," (iii) "25m+9],[" in "(1+m)^(2)-4/n," (v) "4x^(2)-8x+4]]

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