The circle `x^2+ y^2 = 4` cuts the circle `x^2+y^2 + 2x +3y-5=0` in A & B. Then the equation of the circle on AB as a diameter is:

The circle x^(2)+y^(2)=4 cuts the circle x^(2)+y^(2)+2x+3y-5=0 in A and B ,Then the equation of the circle on AB as diameter is

The circle x^2+y^2=4 cuts the circle x^2+y^2+2x+3y-5=0 in A and B , Then the equation of the circle on AB as diameter is

If the circle x^2+y^2+2x+3y+1=0 cuts another circle x^2+y^2+4x+3y+2=0 in A and B , then the equation of the circle with AB as a diameter is

The line 2x -y +6= 0 meets the circle x^2+y^2 -2y-9 =0 at A and B. Find the equation of the circle on AB as diameter.

If x - y + 1 = 0 meets the circle x^(2) + y^(2) + y - 1 = 0 at A and B , then the equation of the circle with AB as diameter is

If x-y+1=0 meets the circle. x^(2)+y^(2)+y-1=0 at A and B , then the equation of the circle with A B as diameter is

The straight line x+y - 1= 0 cuts the circle x^(2) + y^(2) - 6x - 8y = 0 at A and B. Find the equation of the circle of which AB is a diameter.

The line 2x-y+6=0 meets the circle x^(2)+y^(2)-2y-9=0 at A and B. Find the equation of the circle on AB as diameter.

If the circle x^2+y^2+2x+3y+1=0 cuts x^2+y^2+4x+3y+2=0 at A and B , then find the equation of the circle on A B as diameter.