In YDSE, separation between slits is 0.15 mm, distance between slits and screen is 1.5 m and wavelength of light is 589 nm, then fringe width is

In YDSE experiment separation between plane of slits and screen is 1 m . Separation between slits is 2 mm . The wavelength of light is 500 nm . The fringe width is

In YDSE, the distance between the slits is 1 m m and screen is 25cm away from the slits . If the wavelength of light is 6000 Å , the fringe width on the secreen is

In Young's double slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is

In a Young's double slit experiment ,the distance between the slits and the screen is 1 m.If the distance between the slits is 5 mm,the fringe width is found to be 0.1 mm.Calculate the wavelength of the light used.

A YDSE setup is immersed in water (mu = 1.33) . If has slit separation 1 mm and distance between slits and screen is 1.33m. Incident light on slits have wavelength 6300Å . Find the fringe width on screen.

In Young's double-slit experiment, the separation between the slits is halved and the distance between the slits and the screen in doubled. The fringe width is