A particle moves along a straight line its velocity dipends on time as `v=4t-t^(2)`. Then for first `5 s`:

A particle moves along a straight line and its velocity depends on time as v = 3t - t^2. Here, v is in m//s and t in second. Find (a) average velocity and (b) average speed for first five seconds.

A particle moves along a straight line and its velocity depends on time as v = 3t - t^2. Here, v is in m//s and t in second. Find (a) average velocity and (b) average speed for first five seconds.

For a particle moving along a straight line, its velocity 'v' and displacement 's' are related as v^(2) = cs , here c is a constant. If the displacement of the particle at t = 0 is zero, its velocity after 2 sec is:

A particle in moving in a straight line such that its velocity is given by v=12t-3t^(2) , where v is in m//s and t is in seconds. If at =0, the particle is at the origin, find the velocity at t=3 s .

The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

A particle moves in a straight line and its velocity v (in cm/s ) at time t (in second ) is 6t^(2) - 2t^(3) , find its acceleration at the end of 4 seconds.

Find the average velocity of a particle moving along a straight line such that its velocity changes with time as v (m//s) = 4 sin. (pi)/(2) t , over the time interval t = 0 to t = (2n - 1) 2 seconds. (n being any + ve integer).