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Find centre of mass of given rod of line...

Find centre of mass of given rod of linear mass density `lambda=(a+b(x/l)^2)` , x is distance from one of its end. Length of the rod is `l`.

A

`(3l)/4((3a+b)/(2a+b))`

B

`(3l)/4((2a+b)/(3a+b))`

C

`(l)/4((2a+b)/(3a+b))`

D

`l((2a+b)/(3a+b))`

Text Solution

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The correct Answer is:
B
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