`int_0^(pi/2)sin^3x dx=2/3`

int_0^(pi/2) sin x dx

int_0^(pi//2) sin^3 x dx

int_0^(pi) sin3x dx=2/3

int_(0)^(pi) sin 3x dx

int_(0)^(pi) sin 3x dx

int_(0)^(pi//2)sin^(3)x dx=

Prove that int_(0)^(pi/2) sin^(3) x dx=(2)/(3)

By using the properties of definite integrals, evaluate the integrals int_0^(pi/2)(sin^(3/2)x dx)/(sin^(3/2)+cos^(3/2)x)

IF int_0^a sqrtx dx=2a int_0^(pi//2) sin^3 x dx, find int_a^(a+1) x dx .

Evaluate : int_0^(pi/2) sin^3x/(sin^3x+cos^3x)dx .