The tangent to `y=ax^2 + bx+7/2` at `(1, 2)` is parallel to the normal at the point `(-2,2)` on the curve `y=x^2 + 6x + 10` , Find the value of `a` and b`.

The tangent to y = ax ^(2)+ bx + (7 )/(2) at (1,2) is parallel to the normal at the point (-2,2) on the curve y = x ^(2)+6x+10. Then the vlaue of a/2-b is:

The tangent to y = ax ^(2)+ bx + (7 )/(2) at (1,2) is parallel to the normal at the point (-2,2) on the curve y = x ^(2)+6x+10. Then the vlaue of a/2-b is:

The tangent to y=a x^2+b x+7/2a t(1,2) is parallel to the normal at the point (-2,2) on the curve y=x^2+6x+10 , then a=-1 b. a=1 c. b=5/2 d. b=-5/2

The tangent to y=ax^(2)+bx+c at (1,2) is parallel to the normal at the point (-2,2) on the same curve. Find the value of 3a-b+c

The tangent to y=ax^(2)+bx+(7)/(2) at (1,2) is parallel to the normal at the point (-2,2) on the curve y=x^(2)+6x+10, then a a=-1 b.a=1 c.b=(5)/(2) d.b=-(5)/(2)

The tangent to y=ax^(2)+bx+c at (1,-2) is parallel to the normal at the point (-2,2) on the same curve. Find the value of 3a-b+c

The tangent to the curve y=ax^2+bx at (2,-8) is parallel to X-axis then

The tangent to the curve y=ax^2+bx at (2,-8) is parallel to X-axis then