Home
Class 12
CHEMISTRY
5 g of Zn reacts with (I) Excess of NaOH...

5 g of Zn reacts with (I) Excess of NaOH (II) Dilute HCl, then volume ratio of `H_2` gas evolved in (I) and (II) is

A

`2:1`

B

`1:2`

C

`1:1`

D

`1:3`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

When same amount of zinc is treated separately with excess of H_(2)SO_(4) and NaOH , the ratio of volumes of H_(2) evolved is:

KI+I_(2)+HNO_(3) to HIO_(3)+KIO_(3)+NO_(2) If 3 moles of KI and 2 moles of I_(2) are mixed with excess HNO_(3) then volume of NO_(2) gas evolved at NTP is:

When the same amount of Zn is treated with excess of H_(2)SO_(4) and excess of NaOH separately, the ratio of the volume of hydrogen evolved is-

When the same amount of zinc is treated separately with excess of H_(2)SO_(4) and excess of NaOH , the ratio of volumes of H_(2) evolved is:

2KI+I_2+22HHNO_3to2HIO_3+2KIO_3+22NO_2+10H_2O If 3 mole of KI and 2 moles I_2 are reacted with excess of HNO_3 .Volume of NO_2 gas evolved at STP is :

5 g of zinc is treated separately with an excess of (a) dilute hydrochloric acid and (b) aqueous sodium hydroxide The ratio of the volumes of H_(2) evolved in these two reactions is

0.9g Al reacts with dil. HCl to give H_(2) . The volume of H_(2) evolved at STP is (Atomic weight of Al = 27)