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Given K(sp) for Cr(OH)3 is 6 xx 10^(-31)...

Given `K_(sp)` for `Cr(OH)_3` is `6 xx 10^(-31)` then determine `[OH^- ]`. (Neglect the contribution of `OH^-` ions from `H_2O`)

A

`(18 xx 10^(-31))^(1/4) M`

B

`(18 xx 10^(-31))^(1/2) M`

C

`(6 xx 10^(-31))^(1/4) M`

D

`(27 xx 10^(-31))^(1/4) M`

Text Solution

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The correct Answer is:
A
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