`0.48 g` of a substance is dissolved in `10.6` g of `C_(6)H_(6)`.The freezing point of benzene is lowered by `108^(@)C`. What will be the mol.wt. of the (`K_(f)` for benzene =`5`)

0.48 of a substance is dissolved in 10.6 g of C_(6)H_(6) .The freezing point of benzene is lowered by 1.8^(@)C what will be the mol.wt.of the substance ( K_(f) for benzene = 5 )

0.48 g of a substane was dissolved in 10.6g C_(6)H_(6) . The freezing point of benzene was lowered by 1.8^(@)C . Calculate m.w.t. of the substance. Molecular depression constant for benzene is 50 K"mol"^(-1) 100 g .

0.48 g of a substane was dissolved in 10.6g C_(6)H_(6) . The freezing point of benzene was lowered by 1.8^(@)C . Calculate m.w.t. of the substance. Molecular depression constant for benzene is 50 K"mol"^(-1) 100 g .

0.48g of a substance was dissolved in 10.6 g C_6H_6. The freezing point of benzene was lowered by 1.8^@C. Calculate molar mass of the substance. Molecular depression constant for benzene is "5K kg mol"^(-1) .

0.48g of a non volatile solute was dissolved in 10.6g benzene. The freezing point of the solution was lowered by 1.8^@ C. calculate molecular mass of the salute ( K_f for benzene is 5kgmol^(-1) )

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 ^(@)C kg mol ^(-1))

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 K kg mol ^(-1))

When 1 g of arsenic is added to 80 g of benzene, the freezing point of benzene is lowered by 0.19^(@)C(K_(f)=4.9) . The formula of arsenic is (At. wt. of As = 75 ) :

The freezing point of a solution of 2.40 g of biphenyl( C_(12)H_(10) ) in 75.0 g of benzene ( C_(6)H_(6) ) is 4.40^(@)C . The normal freezing point of benzene is 5.50^(@)C . What is the molal freezing point constant (^(@)C//m) for benzene ?