AF (4) ABCDEF is a hexagon, in which the force on A is AB.AC.AD, AE Work, prove that their resultant is 3.AD. AA

If ABCDEF is a regular hexagon, prove that AD+EB+FC=4AB .

If ABCDEF is a regular hexagon, prove that AD+EB+FC=4AB .

If ABCDEF is a regular hexagon, prove that AD+EB+FC=4AB .

If ABCDEF is a regular hexagon then vec AD + vec EB + vec FC =

ABCDEF is a regular hexagon , with the sides AB, AC, AD, AE and AF representing vectors 1 unit , 2 units , 3 units , 4 units and 5 units respetively . Find their resultant ?

If ABCDEF is a regular hexagon of side a, then bar(AB).bar(AF)=

Five forces vec AB,vec AC,vec AD,vec AE and vec AF act at the vertex of a regular hexagon ABCDEF . Prove that the resultant is 6vec AO, where O is the centre of heaagon.

In the given figure, AB = AC and AD = AE. Prove that: BD = CE

ABCDEF is a regular hexagon.Find the vector vec AB+vec AC+vec AD+vec AE+vec AF in terms of the vector vec AD