If `A=[[2,2,1] , [1,3,1] , [1,2,2]]` then `A^3-7A^2+10A=`

If A=[[-1,2],[1,-1]] then, A^(3)-6A^(2)+10A-I=?

If A=[{:(1,2,1),(2,1,3),(1,1,0):}] then prove that A^3-2A^2-7A-4I_3=0 . Hence find A^(-1)

If A=[(3,4,1),(1,0,-2),(-2,-1,2)] then A^(-1) =?

If A=[(2,2),(-3,2)] and B=[(0,-1),(1,0)] then (B^-1A^-1)^-1= (A) [(2,-2),(2,3)] (B) [(3,-2),(2,3)] (C) 1/10 [ (2,2),(-2,3)] (D) 1/10 [(3,-2),(-2,2)]

If A=[(2,2),(-3,2)] and B=[(0,-1),(1,0)] then (B^-1A^-1)^-1= (A) [(2,-2),(2,3)] (B) [(3,-2),(2,3)] (C) 1/10 [ (2,2),(-2,3)] (D) 1/10 [(3,-2),(-2,2)]

If A={:[(1,0,-2),(-2,-1,2),(3,4,1)]:} then A^(-1) =

The inverse of [[3,5,7],[2,-3,1],[1,1,2]] is

If A=[(3,1,2),(1,2,3)] ,B= [(1,0),(2,1),(1,1)] find AB and BA.

Find the inverse of A = [(2,1,3),(4,-1,0),(-7,2,1)] and verify that A^-1 A = I_3 = A A^-1 .