`"Weber"//m^(2)` is equal to

An electron (charge q coulomb) enters a magnetic field of H "weber"//m^(2) with a velocity of vm//s in the same direction as that of the field the force on the electron is

A proton enters a magnetic fiedl of flux density 1.5"weber"//m^(2) with a velocity of 2xx10^(-7)m//sec at an angle of 30^(@) with the field. The force on the proton will be

("Weber" xx "ampere")/("meter") is equal to .

At a place the earth's horizontal component of magnetic field is 0.36xx10^(-4) "Weber"//m^(2) . If the angle of dip at that place is 60^(@) , then the vertical component of earth's field at that place in "Weber"//m^(2) will be approxmately

At a place the earth's horizontal component of magnetic field is 0.36xx10^(-4) "Weber"//m^(2) . If the angle of dip at that place is 60^(@) , then the vertical component of earth's field at that place in "Weber"//m^(2) will be approxmately

In a toroid the number of tuns per unit length is 1000 and current through it is 1/(4pi) ampere. The magnetic field produced inside (in "weber"//m^(2) ) will be

In a toroid the number of tuns per unit length is 1000 and current through it is 1/(4pi) ampere. The magnetic field produced inside (in "weber"//m^(2) ) will be

A solenoid of length 0.2m has 500 turns on it. If 8.71 xx 10^(-6) "Weber"//m^(2) be the magnetic field at an end of the solenoid, then the current flowing in the solenoid is –