[x+1,3,5],[2,x+2,5],[2,3,x+4]|=0

Show that x=1 is a solution of [[x+1,3,5],[2,x+2,5],[2,3,x+4]] =0

The roots of the equation |(1+x,3,5),(2,2+x,5),(2,3,x+4)|=0 are

(i) Solve the equation |{:(x-2,2x-3,3x-4),(x-4,2x-9,3x-16),(x-8,2x-27,2x-64):}|=0 (ii) Prove that x = 1 is a root of the equation (ii) Prove that x=1 is a root of the following equation |{:(x+1,3,5),(2,x+2,5),(2,3,x+4):}|=0 Also find the remaining roots. (iii) If a+b+c=0 then solve |{:(a-x,c,b),(c,b-x,a),(v,a,c-x):}|=0 (iv) Solve |{:(6-x,3,3),(3,4-x,5),(3,5,4-5):}|=0

The roots of the equations |{:(1+x,3,5),(2,2+x,5),(2,3,x+4):}| = 0 are

solve for x, if |[3,-5,2],[4,x+1,-1],[2,x-2,3]|=0

If x!=0 and |(1,x,2x),(1,3x,5x),(1,3,4)|=0 then x=

If |[x^(3)+1,2x,1],[0,5+x,-3],[x-1,x^(2),2]|+|[3,2,1],[-1,5,-2],[0,4,6]|= ax^(5)+bx^(4)+cx^(3)+dx^(2)+ex+f is true for all x in R, then the value of f is

If [(x+1,-3,4),(-5,x+2,2),(4,1,x-6)]=0 then x=

If [[2,3],[4,5]]=[[x,3],[2x,5]] , then x =

" If the trace of the matrix: "A=[[-1,0,2,5],[3,x^(2)-2,4,1],[-1,-2,x-3,1],[2,0,4,x^(2)-6]]" is "0" then "x" is equal to "