A particle of mass `0.1kg` executes `SHM` under a force `F =- 10x (N)`. Speed of particle at mean position is `6 m//s`. Find its amplitude of oscillation.

A particle of mass 0.2 kg executes SHM under a force of F = - 20x N. If speed of particle at mean position is 12 m/s then the amplitude of oscillations is

A particle of mass 0.2 kg exectites SHM under a force of F = - 20x N. If speed of particle at mean position is 12 m/s then the amplitude of oscillations is

A particle of mass 0.1 kg executes SHM under a for F=(-10x) N. Speed of particle at mean position 6m//s . Then amplitude of oscillations is

The frequency of oscilation is ((10)/(pi)) (in Hz) of a particle of mass 0.1 kg which executes SHM is 0.2J at position x = 0.02m . The potential energy is zero at mean position Find the amplitude of osclllation (in meter) :