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" Why is "Cr^(2+)" reducing and "Mn^(3*)...

" Why is "Cr^(2+)" reducing and "Mn^(3*)" oxidising when both have d' configuation "

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Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^4 configuration?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^4 configuration?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Account for the following: (i) Transition elements exhibit higher enthalpies of atomisation. (ii) Cr^(2+) is reducing and Mn^(3+) is oxidising when both have d^4 configuration.